1. Tickets to a fundraiser are $14 if purchased ahead of timearaiser are $14 if purchased ahead of time, and $25 if purchaseddoor. The total amount raised from all ticket sales was $788. If the numberON Tickets purchased ahead of time was five less than the number of tickets Thatwere purchased at the door, how many tickets were purchased at the door

Answer:22 ticketsStep-by-step explanation:Let the number of ticket purchased ahead of time be a and the number of tickets purchased at the door be d.We know that purchasing ahead of time costs $14 while purchasing at the door costs $25. Writing this in equation form yields: 14a + 25d = 788........iNow we also know that ticket purchased ahead of time was 5 less than tickets purchased at the door. Hence, a = d - 5...........iiWe can solve both equations simultaneously .Let's substitute ii into I14( d -5) + 25d = 78814d - 70 + 25d = 78839d - 70 = 78839d = 788 + 7039d = 858d = 858/39 = 22We know a = d - 5This mean a = 22 - 5 = 17