Find the value of z /2 that corresponds to a confidence level of 89.48%.
Accepted Solution
A:
Answer: [tex]1.6202[/tex]Step-by-step explanation:The given confidence level : c= 89.48%.⇒ c= 0.8948 [ in decimal]Then, the significance level = [tex]\alpha= 1-c[/tex] [tex]=\alpha= 1-0.8948=0.1052[/tex]Now, to find the value of [tex]z_{\alpha/2}[/tex] , we need to find the two -tailed z-value using z-table for [tex]\alpha=0.1052[/tex] or we can also find the one-tailed z-value for for [tex]\alpha/2=0.1052/2=0.0526[/tex] Using z-value table , the value is [tex]1.6202[/tex]Hence , [tex]z_{\alpha/2}=1.6202[/tex] that corresponds to a confidence level of 89.48%.