Need help please, does any one know how to do this​

Answer:(6-u)/(2+u)8/(u+2) -1-u/(u+2) +6/(u+2)Step-by-step explanation:There are a few ways you can write the equivalent of this.1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...   (-u+6)/(u+2)Or, you can rearrange the terms so the leading coefficient is positive:   (6 -u)/(u +2)__2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.   -(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)or   8/(u+2) -1Of course, anywhere along the chain of equal signs the expressions are equivalent.__3) You can separate the numerator terms, expressing each over the denominator:(-u +6)/(u+2) = -u/(u+2) +6/(u+2)__4) You can also multiply numerator and denominator by some constant, say 3:   -(3u -18)/(3u +6)You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:   (1+x^2)(6 -u)/((1+x^2)(u+2))